Verification of the Given Statement in Metric Space: d(x, y) Σ from n1 to p of x^n - y^n in R^p
The provided problem involves verifying the given statement within the context of a metric space. Specifically, we are asked to verify whether the function d(x, y) Σ from n1 to p of x^n - y^n defines a metric space for vectors in R^p.
Understanding the Problem Statement
We are given the following statement:
Let X R^p and, for x, y ∈ R^p, define d(x, y) Σ from n1 to p of x^n - y^n.
The goal is to verify if d(x, y) satisfies the properties of a metric space. A metric space involving a function d(x, y) must satisfy the following axioms:
d(x, y) ≥ 0 for all x, y in R^p (non-negativity). d(x, y) 0 if and only if x y (identity of indiscernibles). d(x, y) d(y, x) for all x, y in R^p (symmetry). d(x, y) ≤ d(x, z) d(z, y) for all x, y, z in R^p (triangle inequality).The most challenging part of verifying d(x, y) is to demonstrate that the triangle inequality holds.
Proving the Axioms for the Given Metric
1. Non-Negativity
To prove that d(x, y) ≥ 0 for all x, y ∈ R^p, observe that the expression x_n - y_n for each n is in the real numbers R. Since the sum of non-negative numbers is non-negative, it follows that:
d(x, y) Σ from n1 to p of |x^n - y^n| ≥ 0
2. Identity of Indiscernibles
To prove that d(x, y) 0 if and only if x y, observe that:
d(x, y) 0 implies that x^n - y^n 0 for all n. This means that x^n y^n for each n, and since the components of x and y must be identical, we conclude that x y.
3. Symmetry
To prove symmetry, observe that:
d(x, y) Σ from n1 to p of |x^n - y^n| Σ from n1 to p of |y^n - x^n| d(y, x)
4. Triangle Inequality
The most complex part is proving the triangle inequality. We need to show:
d(x, z) ≤ d(x, y) d(y, z)
Considering each component n, the inequality holds in R because:
|x^n - z^n| ≤ |x^n - y^n| |y^n - z^n|
Summing these inequalities from n1 to p, we get:
d(x, z) Σ from n1 to p of |x^n - z^n| ≤ Σ from n1 to p of (|x^n - y^n| |y^n - z^n|) Σ from n1 to p of |x^n - y^n| Σ from n1 to p of |y^n - z^n| d(x, y) d(y, z)
This confirms that d(x, y) satisfies the triangle inequality.
Since all four axioms are satisfied, d(x, y) defines a metric space on R^p.
Conclusion
In conclusion, the given function d(x, y) Σ from n1 to p of x^n - y^n indeed defines a metric space on R^p. The verification involves checking the non-negativity, identity of indiscernibles, symmetry, and the triangle inequality axioms of a metric space. For a comprehensive understanding and further research, one can refer to the literature on metric spaces and normed vector spaces.
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