Solving for the Unknown in Product and Multiples: A Step-by-Step Guide
Mathematics often involves solving for unknowns through equations that represent relationships between numbers. This article provides a detailed explanation on solving a specific type of problem: finding the value of unknowns when given the product and a multiple relationship. We will go through the steps to solve the given example, xy 900 and 3x 45, to find the values of x and y.
Problem Statement
Given:
xy 900 3x 45Our goal is to find the values of x and y given the two equations above.
Step-by-Step Solution
Solving for x in the Second Equation
The second equation, 3x 45, can be solved directly.
Solution
Divide both sides of the equation by 3 to find x:
3x 45
x 45 / 3 15
Solving for y in the First Equation
Now that we know x 15, we can substitute this value into the first equation, xy 900, to solve for y.
Solution
Substitute x 15 into the first equation:
xy 900
15y 900
Divide both sides by 15 to solve for y:
y 900 / 15 60
Conclusion
The solutions to the given equations are x 15 and y 60. Therefore, the other number is 60.
Verification
To verify our solution, let's check if the values satisfy both original equations:
xy 900 3x 45Substituting x 15 and y 60:
15 * 60 900 (True) 3 * 15 45 (True)Additional Examples
Example 1
Let the two numbers be N and n.
Equations:
3Nn 900 … eqn 1 3N 45 … eqn 2Solution:
From eqn 2, solve for N:
3N 45N 45 / 3 15
Substitute N 15 into eqn 1:
3Nn 90015n 900
Solve for n:
n 900 / 15 60
The numbers are 15 and 60.
Example 2
Let the two numbers be x and y.
Solution:
From the second equation, solve for x:
3x 45x 45 / 3 15
Substitute x 15 into the first equation:
xy 90015y 900
Solve for y:
y 900 / 15 60
The numbers are 15 and 60.
Both verification methods illustrate that 15 and 60 satisfy the original equations, confirming our solution is correct.